Two smooth blocks are placed at a smooth corner as shown. Both the blocks are having mass m. We apply a force F on the small block m. Block A presses the block B in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decrease, as we increase F.
(θ = 37° with horizontal)
As soon as the pressing force on the horizontal wall by block B becomes zero, it will lose the contact with the ground. If the value of F is further increased, the block B will accelerate in upward direction and simultaneously the block A will move toward right.
(i) What is minimum value of F, to lift block B from ground–
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) :
Draw F.B.D
For equilibrium of block A
F = N sin θ
To lift block B from ground
N cos θ ≥ mg (N B = 0)
F sin = 3/4 mg
(ii) :
F = N sin θ
N 1 = mg + N cos θ
N 1 = mg + 4F/3
(iii) :
a sin θ = b cos θ
b = a tan θ = 
g
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